SQL Like Archives - SQL Training Online

September 13, 2017 by Joey Blue Leave a Comment

Learn Basic SQL – 1 Hour Training Course – SQL Training Online

How to write SQL from scratch in 1 hour.

**Full Beginner’s Course**

In this video I show you how to write SQL using SQL Server and SQL Server Management Studio. We go through Creating a Database, Creating Tables, Inserting, Updating, Deleting, Selecting, Grouping, Summing, Indexing, Joining, and other basics you need to get starting writing SQL.

Video: Learn Basic SQL

How to write SQL from scratch in 1 hour.

The following Scripts are used in the training:

--Create Database
Create Database Customer;

--Create Customer Table
create table Customer
(
	FirstName varchar(50),
	LastName varchar(50),
	Age int
);

--Insert Initial Data
insert into Customer (FirstName,LastName,[Age]) values ('Joey','Blue',40);
insert into Customer (FirstName,LastName,[Age]) values ('Barry','Bonds',50);
insert into Customer (FirstName,LastName,[Age]) values ('Mike','Schmidt',60);
insert into Customer (FirstName,LastName,[Age]) values ('Mike','Schmidt1',61);
insert into Customer (FirstName,LastName,[Age]) values ('Mike','Schmidt2',62);
insert into Customer (FirstName,LastName,[Age]) values ('Mike','Schmidt3',63);
insert into Customer (FirstName,LastName,[Age]) values ('Mike','Schmidt4',64);
insert into Customer (FirstName,LastName,[Age]) values ('Mike','Schmidt5',65);

--This deletes mike schmidt
/*
DELETE Customer
where FirstName='Mike'
and LastName Like 'Schmidt_';
*/

--Select Mike Schmidt
select *
from Customer
where FirstName='Mike'
and LastName Like 'Schmidt_';

--Update City on Barry Bonds
update Customer
Set City='Goddard'
where FirstName='Barry'
and LastName = 'Bonds' ;

--Add City to the Customer Table
alter table customer
add City varchar(50);

--Drop the Customer Table
drop table customer;

--Create Customer Table with Primary Key
create table Customer
(
	Id int Primary Key identity(1,1),
	FirstName varchar(50),
	LastName varchar(50),
	Age int,
	City varchar(50)
)

--Insert Customer Data
insert into Customer 
(FirstName,LastName,[Age],City) values ('Joey','Blue',40, 'Goddard');
insert into Customer 
(FirstName,LastName,[Age],City) values ('Barry','Bonds',50, 'San Francisco');
insert into Customer 
(FirstName,LastName,[Age],City) values ('Mike','Schmidt',60, 'KC');

--Create Products Table
create table Products
(
	id int primary key identity(1,1),
	ProductName varchar(50)
)

--Add Price to Products Table
alter table Products
add Price float;

--Select everything from Products table
select * from Products

--Insert Products
insert into Products (ProductName, Price) values ('Baseball', 5.95);
insert into Products (ProductName, Price) values ('Bat', 195.99);

--Create Orders Table
Create table Orders
(
	OrderId int primary key identity(1,1),
	OrderDate Datetime,
	CustomerID int,
	ProductID int
)

--Insert Orders
insert into Orders (OrderDate,CustomerID,ProductID) values (GetDate(),1,1);
insert into Orders (OrderDate,CustomerID,ProductID) values (GetDate(),1,1);
insert into Orders (OrderDate,CustomerID,ProductID) values (GetDate(),2,1);
insert into Orders (OrderDate,CustomerID,ProductID) values (GetDate(),2,1);
insert into Orders (OrderDate,CustomerID,ProductID) values (GetDate(),2,2);
insert into Orders (OrderDate,CustomerID,ProductID) values (GetDate(),2,2);
insert into Orders (OrderDate,CustomerID,ProductID) values (GetDate(),2,2);
insert into Orders (OrderDate,CustomerID,ProductID) values (GetDate(),2,2);
insert into Orders (OrderDate,CustomerID,ProductID) values (GetDate(),3,2);
insert into Orders (OrderDate,CustomerID,ProductID) values (GetDate(),3,2);
insert into Orders (OrderDate,CustomerID,ProductID) values (GetDate(),4,2); --Bad Record

--Select from Tables
select * from Orders;
select * from Products;
select * from Customer;

--Delete Bad Order  **Your OrderId may be different
delete Orders
where OrderId=21;

--Add Foreign Keys to the Orders table
alter table orders
add foreign key (CustomerId) references Customer(Id);

alter table orders
add foreign key (ProductId) references Products(Id);

--Find the Total and Average Price per City
select c.City,sum(p.Price),AVG(p.price) Total
from Orders o 
inner join Products p on o.ProductID=p.id
inner join Customer c on o.CustomerID=c.Id
group by c.City

See the original SQL Training Course for Beginners video.

January 18, 2013 by Joey Blue Leave a Comment

SQL Not Like with Multiple Values

I came across a forum post where someone wanted to use SQL NOT LIKE with multiple values.

They were trying to exclude multiple values from the SQL query, but they were needing to use wildcards.

If you wanted to just filter values without wildcards, you would use the following query.

select *
from table1
where column1 not in ('value1','value2','value3');

The only problem was that they needed to compare using the LIKE operator.

It would be nice if you could just stick some wildcards in the in clause like this:

where column1 not in ('%value1%','%value2%','%value3%')

But, you can’t stick a wildcard inside of the IN clause. So, here is the easiest solution.

select *
from table1
where column1 not like '%value1%'
and column1 not like '%value2%'
and column1 not like'%value3%';

If you want to play around with the Boolean logic, you rearrange the query like this.

select *
from table1
where not (column1 like '%value1%'
or column1 like '%value2%'
or column1 like'%value3%');

SQL Not Like with Multiple Values

What happens if you don’t put those parenthesis in?

Here are a few other posts you might enjoy:

SQL Wildcards | SQL Multiple Filter | How to use the SQL In Statement with Subquery

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June 13, 2012 by Joey Blue Leave a Comment

SQL Like

The SQL Like is the clause that allows you to do wildcard searches in the SQL language.

The Like clause can only be used on string data types (char and varchar in Microsoft SQL Server).

You can use it in a SQL statement anywhere you would normally use the “=” (equal sign).

There are two wildcard characters you can use:

% – Is a multi-character wildcard. Which means it will match more than one character.
_ – The underscore is a single character wildcard. It only matches one character.

Let’s take a look at a few examples.

I want to look at a student table:

select * from student;

Here are the results:

So the student table has 7 rows and 8 columns.

Now, lets find all of the addresses that are designated “Rd”.

I have to do this by searching with the SQL Like clause.

Here is the query to do that:

select * from student where S_ADDRESS LIKE '%Rd%';

The where clause says, “I want to look at the S_ADDRESS column and find everything that has any number of characters, then an Rd, then any number of characters.

Here are the results:

We get 3 records that contain the “RD”.

No what if I wanted to find all of the zip codes that had a third character of 1?

The query would look like this:

select * from student where S_ZIPCODE LIKE '__1%';

Let’s take a look at that LIKE string: ‘__1%’

The first part of that string is actually 2 underscores. That is because we want exactly 2 characters, then we want to see the number 1. (I say number, but it is actually a varchar in the database.)

Here are the results:

I have also used it in a CASE statement inside of the SELECT clause, but I will leave that for another post.

As always, if you have any suggestions for topics you would like for me to blog, or if you have any general comments, leave them below.